Transact SQL (T-SQL) Skill Assessment Quiz 2022 | LinkedIn Skill Assessment Quiz | LinkedIn | MNC Answers
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Transact-SQL (T-SQL)
Q1. Which answer is NOT a type of table index?
- nonclustered
- unique
- heap
- hash
AND
, IN
, LIKE
, and between all belong to a category called what?
Q2. The keywords - joining operations
- linking operations
- criteria operations
- logical operations
Q3. What is the result of this series of statements?
BEGIN TRY
SELECT 'Foo' AS Result;
END TRY
BEGIN CATCH
SELECT 'Bar' AS Result;
END CATCH
- Foo
- FooBar
- Foo Bar
- Bar
Q4. Given these two tables, which query generates a listing showing student names and the department office location where you could reach each student?
-
SELECT Students.first_name, Students.last_name, Departments.office_location FROM Students, Departments;
-
SELECT Students.first_name, Students.last_name, Departments.office_location FROM Students JOIN Departments ON Students.department = Departments.department;
-
SELECT Students.first_name, Students.last_name, Departments.office_location FROM Students JOIN Departments;
-
SELECT Students.first_name, Students.last_name, Departments.office_location FROM Students ON Students.department = Departments.department;
Q5. What is an example of a DDL command in SQL?
-
TRUNCATE TABLE
-
DELETE
-
MERGE
-
DROP
Q6. Given the Games table pictured, which query generates the results shown?
- [ ]
SELECT GameType, MaxPlayers, count(*) AS NumberOfGames
FROM Games
GROUP BY MaxPlayers, GameType
ORDER BY MaxPlayers, GameType;
- [x]
SELECT GameType, MaxPlayers, count(*) AS NumberOfGames
FROM Games
GROUP BY GameType, MaxPlayers
ORDER BY GameType;
- [ ]
SELECT GameType, count(Players) AS MaxPlayers, NumberOfGames
FROM Games
GROUP BY GameType, MaxPlayers
ORDER BY GameType;
- [ ]
SELECT GameType, MaxPlayers, count(*) AS NumberOfGames
FROM Games
GROUP BY GameType
ORDER BY MaxPlayers;
Q7. Which answer is a possible result of the sequence of commands below?
DECLARE @UniqueID uniqueidentifier = NEWID();
SELECT @UniqueID AS Result;
- 1
- bb261196-66a5-43af-815d-123fc593cf3a
- z350mpj1-62lx-40ww-9ho0-4u1875rt2mx4
- 0x2400001155F04846674AD4590F832C0
Q8. You need to find all students that are not on the "Chemistry Cats" team. Which query does NOT work for this task?
- [x]
WHERE team NOT 'Chemistry Cats';
- [ ]
WHERE team <> 'Chemistry Cats';
- [ ]
WHERE team != 'Chemistry Cats';
- [ ]
WHERE NOT team = 'Chemistry Cats';
WHERE
clause should you use to fill in the blank in this query?
Q9. You need to write a query that returns all Employees that have a LastName starting with the letter A. Which -
WHERE LastName = A*
-
WHERE LastName = LIKE '%A%'
-
WHERE LastName LIKE 'A%'
-
WHERE LastName IN ('A*')
Q10. Which query shows the first name, department, and team of all students with the two lowest points?
-
SELECT LIMIT(2) first_name, department, team FROM Students ORDER BY points ASC;
-
SELECT TOP(2) first_name, deprtment, team FROM Students ORDER BY points DESC;
-
SELECT TOP(2) WITH TIES first_name, department, team FROM Students ORDER BY points;
-
SELECT BOTTOM(2) first_name, department, team FROM Students ORDER BY points ASC;
the picture of table is important here and there it can be seen that there are only two value with min points. Secondly, the previous answer was wrong because order by
DESC
will put highest points into the beginning of result list andTOP(2)
will take first two highest points, and we need the lowest points.
Q11. What is the result of this statement?
SELECT FLOOR(-1234.321)
- -1234.3
- -1234
- -1235
- 1234.321
Q12. Which is the best approach to update the last name of the student Donette Figgins to Smith
-
UPDATE Students SET last_name = 'Smith' WHERE email = 'dfiggins@rouxacademy.com';
-
UPDATE Students SET last_name = 'Figgins' WHERE email = 'dfiggins@rouxacademy.com';
-
UPDATE Students SET last_name = 'Figgins' WHERE last_name = 'Smith' AND first-name = 'Donette';
-
UPDATE Students SET last_name = 'Smith' WHERE last_name = 'Figgins' AND first-name = 'Donette';
Q13. Which of these data types is an approximate numeric?
- real
- bit
- decimal
- numeric
Q14. You need to remove all data from a table name Products. Which query fully logs the removal of each record?
-
TRUNCATE FROM Products *;
-
DELETE FROM Products;
-
DELETE * FROM Products;
-
TRUNCATE TABLE Products;
Q15. What is the result of this query?
SELECT 1 / 2 AS Result;
- 0.5
- error
- 0
- 2
Q16. which data type will most efficiently store a person's age in years?
-
float
-
int
-
tinyint
-
bigint
Q17. What is the result of this query?
SELECT 'abc\
def' AS Result;
- abc\def
- abcdef
- error
- abc def
Q18. To select a random student from the table, which statement could you use?
-
SELECT TOP(1) first_name, last_name FROM Students ORDER BY NEWID();
-
SELECT TOP(1) RAND(first_name, last_name) FROM Student;
-
SELECT TOP(1) first_name, last_name FROM Student;
-
SELECT TOP(1) first_name, last_name FROM RAND(Student);
https://www.petefreitag.com/item/466.cfm
Q19. What result is returned after executing the following commands?
DECLARE @MyVariable int;
SET @MyVariable = 1;
GO
SELECT @MyVariable;
- error
- 1
- null
- @MyVariable
Q20. Which statement creates a new database schema named Sales and establish Sharon as the owner?
-
ALTER USER Sharon WITH DEFAULT_SCHEMA = Sales;
-
ALTER USER Sharon SET SCHEMA Sales;
-
CREATE SCHEMA Sales SET OWNER Sharon;
-
CREATE SCHEMA Sales AUTHORIZATION Sharon;
CROSS JOIN
between a table with 4 rows, and one with 5 rows, will give with _ rows.
Q21. The result of a - 1024
- 20
- 0
- 9
WHERE
clause should you use to fill in the blank in this query?
Q22. You need to write a query that returns all products that have a SerialNumber ending with "10_3". Which SELECT ProductID, ProductName, SerialNumber
FROM Products______ ;
-
WHERE SerialNumber LIKE '%10_3'
-
WHERE SerialNumber LIKE ('%10'+'_'+'3')
-
WHERE SerialNumber LIKE '%10"_"3'
-
WHERE SerialNumber LIKE '%10[_]3'
The underscore will match any single character so you must bracket it to match a literal
_
, otherwise you could potentially return a serial number ending in '1013', for example.
FROM
clause is specified, what type of join is assumed?
Q23. When no join type between multiple tables in a query's -
INNER
-
RIGHT
-
LEFT
-
FULL
Q24. How many bytes of storage does the int data type consume?
- 1 byte
- 2 bytes
- 4 bytes
- 8 bytes
RIGHT JOIN
ensure?
Q25. What does a - that only records from the rightmost table will be displayed
- that no records from the rightmost table are displayed if the records dont have corresponding records in the left table
- that records from the rightmost table will be displayed only if the records have a corresponding value in the leftmost table
- that all records from the rightmost table are represented in the result, even if there are no corresponding records in the left table
Q26. You execute the following three queries. What is the result?
Create table students(id int identity(1000,1), firstname varchar(20),
lastname varchar(30));
insert into students(firstname,lastname)values('mark','twain');
select * from students;
studentid firstname lastname 1 1001 mark twain
studentid firstname lastname 1 1 mark twain
studentid firstname lastname 1 1000 mark twain
studentid firstname lastname 1 null mark twain
Q27. Given a table with the following structure, which query returns all student names with the highest grade?
CREATE TABLE Students (
StudentName varchar(50),
Grade int );
-
SELECT StudentName FROM Students WHERE Grade = MAX(Grade);
-
SELECT TOP(1) StudentName FROM Students ORDER BY Grade;
-
SELECT TOP(1) WITH TIES StudentName FROM Students ORDER BY Grade DESC;
-
SELECT StudentName, MAX(Grade) FROM Students ORDER BY Grade DESC;
top(1)
with ties will take the highest grade and all other students with the same grade (because they are order by grade) and matches the highest grade.
Q28. What role does "inventory" play?
select bookid, boooktitle, bookauthor,quantityonhand from inventory.books;
- you only want to see results from books currently in inventory
- it instructs the query engine to find the books table in the inventory schema
- it instructs the query engine to find the books table in the inventory database
- it instructs the query engine to join the books table to the inventory schema
select * from dbo.books
heredbo
is a schema and the inventory is also schema. If we'd like to specify a database we should usedb_name.schema_name.table_name
INNER JOIN
between table1 and table2?
Q29. What is the result of an - Only records that have corresponding entries in table1 and table2 are displayed.
- No records from table1 are ever displayed.
- All records from table1 are displayed, regardless of whether the records have a corresponding row in table2
- Only records that have no corresponding records in table1 or table2 are displayed.
Q30. To remove all of the content from the Students table but keep the schema, which statement should you use?
-
TRUNCATE TABLE Students;
-
TRUNCATE * FROM Students;
-
DROP TABLE Students;
-
REMOVE * FROM Students;
CREATE TABLE
statement below. Which option, when placed in the blank space, ensures that the BookISBN column will not contain any duplicate values?
Q31. Review the CREATE TABLE Books (
BookID int PRIMARY KEY,
BookISBN char(13) NOT NULL _____,
BookTitle nvarchar(100) NOT NULL
);
-
NO DUPLICATES
-
UNIQUE CONSTRAINT AK_Books_BookISBN
- D
UPLICATE CONSTRAINT (AK_Books_BookISBN)
-
CONSTRAINT AK_Books_BookISBN UNIQUE
Q32. Given a table with the following structure, which query will not return the lowest grade earned by any student?
CREATE TABLE Students (
StudentName varchar(50),
Grade int
);
- [ ]
SELECT StudentName
FROM Students
WHERE Grade = (SELECT MIN(Grade) FROM Student);
- [ ]
SELECT TOP(1) Grade
FROM Students
ORDER BY Grade;
- [ ]
SELECT MIN(Grade)
FROM Students
- [x]
SELECT MIN(Grade)
FROM Students
ORDER BY Grade;
Explanation: Column
Students.Grade
is invalid in theORDER BY
clause because it is not contained in either an aggregate function or theGROUP BY
clause.
- [x]
SELECT MIN(Grade)
FROM Students
GROUP BY Grade;
Explanation: Grouping will return a list of all grades grouped by grade. The prompt wants just one returned row.
Q33. Refer to the figure below.
-
UPDATE Students SET last_name='Smith', email = 'dsmith@rouxacademy.com' WHERE id='56295';
-
UPDATE Students SET last_name='Smith' AND email = 'dsmith@rouxacademy.com' WHERE id='56295';
-
UPDATE Students SET last_name='Smith' AND email = 'dsmith@rouxacademy.com' WHERE id=56295;
-
UPDATE Students SET last_name='Smith', email = 'dsmith@rouxacademy.com' WHERE id=56295;
Q34. You would like to have a record added to a TableB every time a record is modified in TableA. What technique should you look at implementing?
- You should create a DML trigger on the server.
- You should create a DDL trigger on the database.
- You should create a DML trigger on TableA.
- You should create a DML trigger on TableB.
Q35. What is the problem with this code?
DECLARE @Counter int;
SET @Counter = 1;
WHILE @Counter > 0
BEGIN
SET @Counter = @Counter +1;
END;
- There is no END WHILE statement;
- The local variable is not available to the WHILE block.
- The query causes an infinite loop.
- "Counter" is an invalid variable name.
Q36. Which is the right query to change the name of the Philosophy Pandas team to the Philosophy Parrots?
-
UPDATES Students SET team = 'Philosophy Parrots' WHERE team = 'Philosophy Pandas';
-
UPDATES Students SET team =
Philosophy ParrotsWHERE team =
Philosophy Pandas;
-
UPDATES Students SET team = "Philosophy Parrots" WHERE team = "Philosophy Pandas";
-
UPDATES Students SET team = Philosophy Parrots WHERE team = Philosophy Pandas;
Q37. What is the result of this query?
SELECT 123+'123' AS Result;
- error
- '123''123'
- 123123
- 246
SELECT
statements, removing duplicates, which keyword can you use?
Q38. To combine the results of two or more - DEDUPE
- SELECT
- MERGE
- UNION
Q39. You run this series of statements. What is the final result?
CREATE TABLE MyTable (MyValue int);
INSERT INTO MyTable VALUES (1);
WHILE (SELECT MyValue FROM MyTable) < 5
BEGIN
UPDATE My Table SET MyValue = MyValue + 1;
END;
SELECT MyValue AS Result FROM MyTable;
- 5
- error
- 1
- 6
Q40. Is there an error with this query? If so, which statement best describes the problem?
SELECT OrderID, SUM(LineTotal) AS SubTotal
FROM Sales
WHERE SUM(LineTotal) > 1000
GROUP BY OrderID
ORDER BY OrderID;
- Yes, a
WHERE
clause cannot be used with an aggregate function. - Yes, you cannot
GROUP BY
andORDER BY
the same field. - No, there is nothing wrong with this query.
- Yes, the
WHERE
clause should use theSubTotal
alias.
Q41. You created the two tables below. Later, you decide that you want the database to remove all books from the Books table if the related publisher is deleted from the Publishers table. What command should you run?
CREATE TABLE Books (
BookID int PRIMARY KEY,
BookTitle nvarchar(100) NOT NULL,
PublisherID int NOT NULL
);
CREATE TABLE Publishers (
PublisherID int PRIMARY KEY,
PublisherName nvarchar(50)
);
- [ ]
ADD CONSTRAINT FK Books_PublisherID
FOREIGN KEY (PublisherID)
REFERENCES Publishers (PublisherID) ON UPDATE SET NULL
- [ ]
ADD CONSTRAINT FK Books_PublisherID
FOREIGN KEY (PublisherID)
REFERENCES Publishers (PublisherID) ON DELETE CASCADE
- [ ]
ADD CONSTRAINT FK_Books_PublisherID
FOREIGN KEY (PublisherID)
REFERENCES Publishers (PublisherID)
- [ ]
ADD CONSTRAINT FK_Publishers_PublisherID
FOREIGN KEY (PublisherID)
REFERENCES Books (PublisherID) CASCADE DELETE
Q42. Your database currently has a table called Inventory in the Warehouse schema. You need to move the table to the Products schema. Which query accomplishes this goal?
-
ALTER SCHEMA Products TRANSFER Warehouse.Inventory;
-
ALTER TABLE Warehouse.Inventory TRANSFER Products.Inventory;
-
ALTER TABLE Warehouse.Inventory ADD SCHEMA Products;
-
ALTER SCHEMA Warehouse ADD TABLE Inventory;
Q43. Which option—when placed in the blank space—establishes the PersonlD column as the primary key for the table with a nonclustered index?
CREATE TABLE People (
PersonID int NOT NULL,
PersonName nvarchar(50),
_______
);
-
INDEX ON PersonID (PRIMARY KEY PK_People)
-
ADD NONCLUSTERED PRIMARY KEY CONSTRAINT PK_People ON PersonID
-
CONSTRAINT PK_People PRIMARY KEY NONCLUSTERED (PersonID)
-
PRIMARY KEY CONSTRAINT (PersonID) NONCLUSTERED INDEX
Q44. Which statement could you use to select a random student from this table?
-
SELECT TOP(1) first_name, last_name FROM Students ORDER BY NEWID();
-
SELECT TOP(1) RAND(first_name, last_name) FROM Student;
-
SELECT TOP(1) first_name, last_name FROM Student;
-
SELECT TOP(1) first_name, last_name FROM RAND(Student);
Z:\Backups
directory. Which query should you use?
Q45. You need to create a simple database backup in the server's -
BACKUP MyDatabase TO LOCATION = 'Z:\Backups\MyDatabase.bak';
-
CREATE BACKUP (DATABASE = 'MyDatabase' TO DISK = 'Z:\Backups\MyDatabase. bak');
-
BACKUP DATABASE MyDatabase ON 'Z:\Backups\MyDatabase.bak';
-
BACKUP DATABASE MyDatabase TO DISK = 'z:\Backups\MyDatabase.bak';
Q46. Suppose you want to have the name of a transaction called myTransaction recorded in the transaction log. Which statement represents the best way to accomplish this?
-
BEGIN TRAN myTransaction BEGIN LOG;BEGIN TRAN myTransaction BEGIN LOG;
-
BEGIN TRAN myTransaction WITH LOG;BEGIN TRAN myTransaction WITH LOG;
-
BEGIN TRAN myTransaction WITH MARK;BEGIN TRAN myTransaction WITH MARK;
-
BEGIN TRAN WITH MARK myTransaction;BEGIN TRAN WITH MARK myTransaction;
Q47. Though not currently a requirement, what will a future release of SQL Server require of all SQL statements?Though not currently a requirement, what will a future release of SQL Server require of all SQL statements?
-
All statements must end with a semicolon.
-
All statements must operate on a table of data.
-
All statements must always be written in uppercase letters.
-
All statements must include more than one variable.
Q48. Which is the best approach to update the last name and email address of a student with ID 56295?
-
UPDATE Students SET last_name='Smith', email = 'dsmith@rouxacademy.com' WHERE id='56295';
-
UPDATE Students SET last_name='Smith', email = 'dsmith@rouxacademy.com' WHERE id=56295;
-
UPDATE Students SET last_name='Smith' AND email = 'dsmith@rouxacademy.com' WHERE id=56295;
-
UPDATE Students SET last_name='Smith' AND email = 'dsmith@rouxacademy.com' WHERE id='56295';
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